[Django]-What is the SQL ''LIKE" equivalent on Django ORM queries?

319👍

Use __contains or __icontains (case-insensitive):

result = table.objects.filter(string__contains='pattern')

The SQL equivalent is

SELECT ... WHERE string LIKE '%pattern%';

@Dmitri’s answer below covers patterns like ‘pattern%’ or ‘%pattern’

55👍

contains and icontains mentioned by falsetru make queries like SELECT ... WHERE headline LIKE '%pattern%

Along with them, you might need these ones with similar behavior:
startswith, istartswith, endswith, iendswith

making

SELECT ... WHERE headline LIKE 'pattern%

or

SELECT ... WHERE headline LIKE '%pattern

29👍

This can be done with Django’s custom lookups. I have made the lookup into a Django-like-lookup application. After installing it the __like lookup with the % and _ wildcards will be enabled.

All the necessary code in the application is:

from django.db.models import Lookup
from django.db.models.fields import Field


@Field.register_lookup
class Like(Lookup):
    lookup_name = 'like'

    def as_sql(self, compiler, connection):
        lhs, lhs_params = self.process_lhs(compiler, connection)
        rhs, rhs_params = self.process_rhs(compiler, connection)
        params = lhs_params + rhs_params
        return '%s LIKE %s' % (lhs, rhs), params

9👍

result = table.objects.filter(string__icontains='pattern')

Case insensitive search for string in a field.

4👍

In order to preserve the order of the words as in the sql LIKE ‘%pattern%’ statement I use iregex, for example:

qs = table.objects.filter(string__iregex=pattern.replace(' ', '.*'))

string methods are immutable so your pattern variable will not change and with .* you’ll be looking for 0 or more occurrences of any character but break lines.

By using the following to iterate over the pattern words:

qs = table.objects
for word in pattern.split(' '):
    qs = qs.filter(string__icontains=word)

the order of the words in your pattern will not be preserved, for some people that could work but in the case of trying to mimic the sql like statement I’ll use the first option.

3👍

full example : lets say we have table called DjangTable with string field name file_name and we want to create Django filter equivalent to the query that match space in the string file_name in mysql:

SELECT * FROM DjangTable WHERE file_name LIKE '% %' 
class DjangTable(UTModel):


    ...
    file_name = models.CharField(max_length=255, null=False)
    ...

in Django using python it will be :

pattern = ' ' # same as mysql LIKE '% %'
DjangTable.objects.filter(file_name__contains=pattern)

0👍

SQL "LIKE" equivalent on Django ORM queries:

SQL Query:

SELECT * or any_column_name 
FROM table_name
WHERE string LIKE '%pattern%';

Equivalent Django ORM Query Pattern:

qs = Model.objects.filter(column_name__contains='string_pattern')

Equivalent Django ORM Query Example: If the model is: Book and column is: id, name etc. then the ORM Query will be like below:

qs = Book.objects.filter(name__contains='programming')

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