[Vuejs]-Vue directive don't render element if condition is false

by

1👍

✅

You already have a user store that can be injected into any component.

I suggest computing often-used keys like isAdmin, isSuperAdmin in the store:


const isAdmin computed(() => hasRole('admin'))

In your components, you can use the following pattern to conditionally render items:

<template>
<div v-if="isAdmin">
  <h1>Super Secret Stuff</h1>
</div>
</template>

<script setup>
const { isAdmin } = useUserStore()
</script>

This circumvents direct DOM manipulation, which is always a pain and often a bad practice.

👤Barthy

1👍

I think that using directives for this purpose, is not the right way, in order to avoid component rendering.

To avoid a component to be rendered you should, insted, use the v-if condition.

To share the logic of hasRole between your component, you can use mixins, or just write a small plugin you can add to Vue app.

👤Mario Santini

0👍

Here is the corrected code I have.

import {useUserStore} from "@/stores/UserStore.js";

export default {
  inserted(el, binding, vnode) {
    const { value } = binding
    const super_admin = "admin";
    const userStore = useUserStore()
    await userStore.fill()
    const roles = userStore.getUser.roles

    if (value && value instanceof Array && value.length > 0) {
      const roleFlag = value

      const hasRole = roles.some(role => {
        return super_admin === role || roleFlag.includes(role)
      })

      if (!hasRole) {
        el.parentNode && el.parentNode.removeChild(el)
      }
    } else {
      throw new Error(`Missing role value"`)
    }
  }
}
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