[Answer]-Validating a django formset via ajax

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1👍

I wound up changing my javascript to explicitly send a POST with the appropriate values rather than rely on the default “submit” behavior of the form in the dialog. The new code looks something like this:

function edit_model(model_id) {

  var url = "http://www.mydomain.com/edit_model/?i=" + model_id

  var edit_model_dialog = $("<div></div>");
  $.ajax({
     url        : url,
     type       : "GET",
     cache      : false,
     success    : function(data) {
       var title = "here is a form to edit the model"
       edit_model_dialog(data);
       edit_model_dialog.dialog({
         title : title,
         modal : true,
         dialogClass: "no-close",
         close   : function() {
           $(this).dialog("destroy");
         },
         // HERE IS THE NEW BIT...
         buttons : {
           ok : function() {
             // GET THE DATA FROM THE FORM IN THE DIALOG...
             var form_data = $(this).find("the_form").serialize();
             $.ajax({
               url   : url
               // EXPLICITLY SEND IT AS A POST...
               type  : "POST",
               data  : form_data,
               cache : false,
               success : function(data) {
                 if (data == "success") {
                   $(edit_model_dialog).dialog("close");
                 }
                 else {
                   $(edit_model_dialog).html(data);
                 }
               }
             });
           },
           cancel : function () {
             $(edit_model_dialog).dialog("close");
           }
         }
       }).dialog('open');
     }
   })
👤trubliphone

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