[Django]-Using HttpResponseRedirect, but browser is not showing correct URL

Didn’t test it, but:

urls.py

urlpatterns = patterns('',    
    url(r'^$', 'django.contrib.auth.views.login'),
    url(r'^logout$', 'screening.views.logout_view'),
    url(r'^home/$', 'screening.views.home'),
    url(r'^quex/new/$', 'screening.views.new_quex'),
    # others omitted
    url(r'^quex/(?P<identifier>\w{8})/(?P<question_number>\d+)/$', 'screening.views.quex', name='quex-view'),
)

views.py

from django.core.urlresolvers import reverse_lazy


def quex(request, identifier, question_number):

    next_question = int(question_number) + 1
    if request.method == 'POST': # If the form has been submitted...
        form = ContactForm(request.POST) # A form bound to the POST data
        if form.is_valid(): # All validation rules pass

            response_url = reverse_lazy('quex-view', kwargs={'identifier':identifier, 'question_number':next_question})
            return HttpResponseRedirect(reponse_url) 
    else:
        form = QuestionForm() # An unbound form

    return render_to_response('questionnaire.html', {
        'form': form,
        'identifier' : identifier,
        'question_number' : question_number},
        RequestContext(request)

Your last quex regex ends in /, not /$. Change that first. You say you’ve switched to reverse in the view so that single regex change should work.

You are getting this error because of you are calling views method as a recursion. here return HttpResponseRedirect(‘/quex/’ + id + ‘/’ + str(next_question)) is call again same method only difference is request.method will change from POST to GET. and second time as a get method this will call return render_to_response and you will see page. I hape you will get my through.

Change your code like this:

def quex(request, id, question_number):
    next_question = int(question_number) + 1
    if request.method == 'POST': # If the form has been submitted...
        form = ContactForm(request.POST) # A form bound to the POST data
        if form.is_valid(): # All validation rules pass
            # Process the data in form.cleaned_data
            # ...
            # Next line I have written, so you will get same value of question_number as you get after returning from HttpResponseRedirect
            question_number =  next_question + 1 
    form = QuestionForm() # An unbound form

    return render_to_response('questionnaire.html', {
        'form': form,
        'id' : id,
        'question_number' : question_number},
        RequestContext(request)

This code will work as your current code. without any bug.
Hope this will help full to you.

What the browser shows in the URL bar will depend on your client-side code:

• simple HTML forms will redirect correctly.
• jquery’s $.ajax() call will not redirect by default, so even though the code works, the client does not redirect.

def quex(request, identifier, question_number):

    next_question = int(question_number) + 1
    if request.method == 'POST':
        form = ContactForm(request.POST)
        if form.is_valid():
            return HttpResponseRedirect('/quex/' + identifier + '/' + str(next_question)) 
    else:
        form = QuestionForm() # An unbound form

    return render_to_response('questionnaire.html', {
        'form': form,
        'id' : identifier,
        'question_number' : question_number})

1. your render_to_response() is missing the trailing )
2. the 3rd argument to render_to_response() is optional. I usually leave it off. However I would pass it in as a named argument as-per the documentation. enter link description here
3. finally: your def quex(request, id, question_number): should be def quex(request, identifier, question_number): in order to match the url pattern. Also change the id references in the body of quex to be identifier ( which I included in the sample code)