[Django]-TypeError: login() got an unexpected keyword argument 'template_name'

The login function that you’re using is not actually a view. It’s just a regular function which you can use to authenticate a user and set the session cookie, etc.

Read the docs for it’s usage: https://docs.djangoproject.com/en/2.2/topics/auth/default/#django.contrib.auth.login

Judging by your code, it appears you want to use LoginView.

from django.contrib.auth.views import LoginView

def landing_validation(request):
    login_response = LoginView.as_view()(request, template_name='landing.html')

    return login_response

In Django 2.2 app I fixed similar error by using LoginView instead of login.

File users/urls.py:

from django.conf.urls import url
# from django.contrib.auth.views import login
from django.contrib.auth.views import LoginView

from . import views

app_name = 'users'
urlpatterns = [
    # url(r'^login/$', login, {'template_name': 'users/login.html'}, name='login'),
    url(r'^login/$', LoginView.as_view(template_name='users/login.html'), name='login'),
]

You can see that django.contrib.auth.login takes request, user, and an optional backend. There is no template_name. This hasn’t changed recently, so I think you would get the same problem in 1.11, too.

It looks like you want a view function, but django.contrib.auth.login is not that. It doesn’t return a response.