[Answer]-Twitter style errors for Django TastyPie

1👍

To customize your error output, you can override is_valid method of the resource itself.

MyResource(ModelRecource):
    def is_valid(self, bundle):
        errors = self._meta.validation.is_valid(bundle, bundle.request)

        if errors:
            bundle.errors['errors'] = [errors]
            return False

        return True

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