1👍
updated:
values() returns a Queryset that behaves similar to a dict. Simply try
=conta1['contar'] + 1
or
=conta[0]['contar']
to debug print(conta)
and you will see it
please add the error trace in future posts
0👍
You can determine the maximum contar
and then increment this with one, like:
from django.db.models import Max
def atualizar(request, contador):
lista = factura.objects.filter(contador__contador=contador)
conta = lista.aggregate(max_contar=Max('contar'))['max_contar'] or 0
cont = get_object_or_404(cliente, contador=contador)
if request.method == 'POST':
data1 = request.POST['data1']
factura_nr = request.POST['factura_nr']
data2 = request.POST['data2']
consumo = request.POST['consumo']
dados = factura.objects.create(
contador=cont,
contar=conta + 1, # to incremet here
consumo=consumo,
data1=data1,
data2=data2,
factura_nr=factura_nr,
)
return redirect('name-of-some-view')
return render(
request, 'tabela.html', {'lista': lista, 'cont': cont, 'conta': conta}
)
Note: Models in Django are written in PascalCase, not snake_case,
so you might want to rename the model fromtofactura
Factura
.
Note: It is better to use a
Form
[Django-doc]
than to perform manual validation and cleaning of the data. AForm
will not
only simplify rendering a form in HTML, but it also makes it more convenient
to validate the input, and clean the data to a more convenient type.
Note: It is often better to use
get_object_or_404(…)
[Django-doc],
then to use.get(…)
[Django-doc] directly. In case the object does not exists,
for example because the user altered the URL themselves, theget_object_or_404(…)
will result in returning a HTTP 404 Not Found response, whereas using
.get(…)
will result in a HTTP 500 Server Error.
Note: In case of a successful POST request, you should make a
redirect
[Django-doc]
to implement the Post/Redirect/Get pattern [wiki].
This avoids that you make the same POST request when the user refreshes the
browser.
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