[Answered ]-Slugfield URL implementation in Django

I have used django-autoslug to great success. You can find a live example here.

SlugField is just a char field with a little syntactic sugar.

You will want to name your slug just slug so django can find it automatically in the URL resolution and passes the right parameter to views.

Your amended code would look like:

from autoslug import AutoSlugField
from django.db import models

class Newlist(models.Model): # Classes start with uppercase names by default
    user = models.ForeignKey(User)
    list_name = models.CharField(max_length = 100,)
    picture = models.ImageField(upload_to='profiles/', default = "/media/profiles/default.jpg")
    slug = AutoSlugField(populate_from='list_name')
    def __str__(self):
        return self.list_name

Your View:

def mylistpage(request,username, slug):

    context = RequestContext(request)

    #make sure that the user is authenticated
    if username == request.user.username:
        #If the user is authenticated, then perform the following functions to the page
        if request.user.is_authenticated():
            #Store the current user request object into a variable
            user = User.objects.get(username=username)

            #Store the list name to the item that starts with the url input
            listname = request.user.newlist_set.filter(slug=slug)

            listitems = request.user.newlist_set.all()
            if not listname:
                return redirect('/notfound')
    else:
        return redirect('/notfound')

    return render_to_response('listview.html', {'lista': listname}, context)

urls.py

url(r'^user/(?P<username>\w+)/list/(?P<slug>[\w-]+)/$', mylistpage, name='lists'),