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I changed latest line of */my-venv/lib/python2.7/site-packages/sentry/wsgi.py
as below and now worked:
application = WSGIHandler() # Sentry(FileWrapperWSGIHandler())
But i think that sentry cant monitor and show internal exceptions, and in next step i changed the application
variable definition line as below:
application = Sentry(WSGIHandler()) # Sentry(FileWrapperWSGIHandler())
And i think this code working correctly.
๐คM.javid
Source:stackexchange.com