[Answer]-Sending arbitrary request data in Django

You need to use function render_to_response, like what you didi to device_qa_build_form.html in your code.

You will have to modify qa_results.html to give it a variable called form, then using render_to_response. Something like this:

if request.method == 'POST':
    form = Device_qa_Form(request.POST )
    if form.is_valid():
      cd = form.cleaned_data

      Device_build_test.set_up(
        cd
     )
    # return HttpResponseRedirect('/qa_results.html/')
    return render_to_response('/qa_results.html/', {'form':form})
else:
    form = Device_qa_Form()

return render_to_response('device_qa_build_form.html', {'form':form} )

Here is instruction of render_to_response for you.
https://docs.djangoproject.com/en/1.7/topics/http/shortcuts/

I got it to work this way… getting the returned data and creating the context sending it on. If anyone thinks this is a bad idea let me know.

 if request.method == 'POST':
    form = Device_qa_Form(request.POST )
    if form.is_valid():
      cd = form.cleaned_data

      results = Device_build_test.set_up(
        cd
     )
     t = loader.get_template('qa_results.html')
     c = Context({'results':results})
     return HttpResponse( t.render(c))
 else:
    form = Device_qa_Form()

return render_to_response('device_qa_build_form.html', {'form':form} )