[Django]-Send Custom Parameters to Django Signals

by

4👍

You can send any additional parameters in a signal as keyword arguments:

@receiver(post_save, sender=post_data)
def addToRedis(sender, instance, **kwargs):
    # kwargs['extra_param']

How to send:

my_signal.send(sender=self.__class__, extra_param='...')

If you have no access to the signal send function (eg REST framework internals), you can always use a custom signal.

👤Wtower

3👍

This Answer the with Respect to Django Rest:

in your views.py

my_obj = Mymodel()
my_obj.your_extra_param = "Param Value" # your_extra_param field (not Defined in Model)
my_obj.save()
post_save.connect(rcver_func,sender=Mymodel,weak=False)

and define a signal.py with following

from django.db.models.signals import post_save
from django.dispatch import receiver
from .models import Mymodel

@receiver(post_save,sender=Mymodel)
def rcver_func(sender, instance, created,**kwargs):
    if created:
        received_param_value = instance.your_extra_param # same field as declared in views.py
👤Lubdhak

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