[Solved]-Run bash script with Django

by

16👍

✅

You can do this with empty form.

In your template make a empty form

# index.html
<form action="{% url 'run_sh' %}" method="POST">
    {% csrf_token %}
    <button type="submit">Call</button>
</form>

Add url for your form

from django.conf.urls import url

from . import views

urlpatterns = [
    url(r'^run-sh/$', views.index, name='run_sh')
]

Now in your views.py you need to call the bash.sh script from the view that returns your template

import subprocess

def index(request):
    if request.POST:
        # give the absolute path to your `text4midiAllMilisecs.py`
        # and for `tiger.mid`
        # subprocess.call(['python', '/path/to/text4midiALLMilisecs.py', '/path/to/tiger.mid'])

        subprocess.call('/home/user/test.sh')

    return render(request,'index.html',{})

My test.sh is in the home directory. Be sure that the first line of bash.sh have sh executable and also have right permission. You can give the permissions like this chmod u+rx bash.sh.

My test.sh example

#!/bin/sh
echo 'hello'

File permision ls ~

-rwxrw-r--   1 test test    10 Jul  4 19:54  hello.sh*
👤Druta Ruslan

2👍

You can use python module subprocess in your view.


import subprocess

def your_view(request):

    subprocess.call('your_script.sh')
👤Muhtar

2👍

You can refer my blog for detailed explanation >>

http://www.easyaslinux.com/tutorials/devops/how-to-run-execute-any-script-python-perl-ruby-bash-etc-from-django-views/

I would suggest you to use Popen method of Subprocess module. Your shell script can be executed as system command with Subprocess.

Here is a little help.

Your views.py should look like this.

from subprocess import Popen, PIPE, STDOUT
from django.http import HttpResponse

def main_function(request):
    if request.method == 'POST':
            command = ["bash","your_script_path.sh"]
            try:
                    process = Popen(command, stdout=PIPE, stderr=STDOUT)
                    output = process.stdout.read()
                    exitstatus = process.poll()
                    if (exitstatus==0):
                            result = {"status": "Success", "output":str(output)}
                    else:
                            result = {"status": "Failed", "output":str(output)}

            except Exception as e:
                    result =  {"status": "failed", "output":str(e)}

            html = "<html><body>Script status: %s \n Output: %s</body></html>" %(result['status'],result['output'])
            return HttpResponse(html)

In this example, stderr and stdout of the script is saved in variable ‘output‘, And exit code of the script is saved in variable ‘exitstatus‘.

Configure your urls.py to call the view function “main_function“.

url(r'^the_url_to_run_the_script$', main_function)

Now you can run the script by calling http://server_url/the_url_to_run_the_script

👤Nijil

1👍

Do it with Python:

With Subprocess:

import subprocess
proc = subprocess.Popen("ls -l", stdout=subprocess.PIPE)
output, err = proc.communicate()
print output

Or with os module: 

import os
os.system('ls -l')
👤Shameer Kashif

0👍

From Python 3.5 onwards, subprocess.run() is the recommended approach

As per the doc;

The recommended approach to invoking subprocesses is to use the run()
function for all use cases it can handle. For more advanced use cases,
the underlying Popen interface can be used directly.

The run() function was added in Python 3.5; if you need to retain
compatibility with older versions, see the Older high-level API
section.

As in this example,

import subprocess

def index(request):
    if request.POST:
        subprocess.run(['/home/josema/parser.sh'])

    return render(request,'nuevaCancion.html',{})
👤Anupam

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