[Django]-"Post Image data using POSTMAN"

185👍

✅

That’s not how you send file on postman. What you did is sending a string which is the path of your image, nothing more.

What you should do is:

After setting request method to POST, click to the ‘body’ tab.
Select form-data. At first line, you’ll see text boxes named key and value. Write ‘image’ to the key. You’ll see value type which is set to ‘text’ as default. Make it File and upload your file.
Then select ‘raw’ and paste your JSON file. Also, just next to the binary choice, you’ll see ‘Text’ is clicked. Make it JSON.

You’re ready to go.

In your Django view,

from rest_framework.views import APIView
from rest_framework.parsers import MultiPartParser
from rest_framework.decorators import parser_classes

@parser_classes((MultiPartParser, ))
class UploadFileAndJson(APIView):

    def post(self, request, format=None):
        thumbnail = request.FILES["file"]
        info = json.loads(request.data['info'])
        ...
        return HttpResponse()

👤Cagatay Barin

[Django]-Sort order of Django Admin records

37👍

Now you can hover the key input and select “file”, which will give you a file selector in the value column:

👤theisof

17👍

The accepted answer works if you set the JSON as a key/value pair in the form-data panel (See the image hereunder)

Nevertheless, I am wondering if it is a very clean way to design an API. If it is mandatory for you to upload both image and JSON in a single call maybe it is ok but if you could separate the routes (one for image uploading, the other for JSON body with a proper content-type header), it seems better.

👤MarAja

14👍

It can be done in three ways

1. Go to Body > Form-data > Select Files in the column

2. Go to Body > binary > Select File

3. Encode image to base64 string and pass it through postman Body > raw > JSON like mentioned in the attached screenshots

Then on the server-side, you can decode it that way

import base64
decode = base64.b64decode(data)

from django.core.files.base import ContentFile
file = ContentFile(decode, name=name)

Note:
You could encode the file to base64 through that link and send it in the curl.

https://base64.guru/converter/encode/file

👤Umar Asghar

7👍

It works for me:

Goto Body
Form-data
Chose "File" in the first cell properties

👤swor

2👍

Follow the below steps:

No need to give any type of header.
Select body > form-data and do same as shown in the image.
Now in your Django view.py

def post(self, request, *args, **kwargs):
    image = request.FILES["image"]
    data = json.loads(request.data['data'])
    ...
    return Response(...)