1👍
✅
from django.core.files.base import ContentFile
from PIL import ImageOps, Image as pil_image
import os.path
import json
def ajax_upload(request):
if request.method == 'POST':
newfile = Image()
newfile.user = request.user
file_content = ContentFile(request.raw_post_data)
file_name = request.GET.get('file')
newfile.image.save(file_name, file_content)
newfile.thumbnail.save(file_name, file_content)
#opening and resizing the thumbnail
path = os.path.join(settings.MEDIA_ROOT, newfile.thumbnail.url)
thumb_file = pil_image.open(path)
if thumb_file.mode not in ("L", "RGB"):
thumb_file = thumb_file.convert("RGB")
thumb_image_fit = ImageOps.fit(thumb_file, (100, 100), pil_image.ANTIALIAS)
thumb_image_fit.save(path)
#===============================================================
results = {
'image':
{
'url': newfile.image.path,
'width': newfile.image.width,
'height': newfile.image.height
},
'thumbnal':
{
'url': newfile.thumbnail.path,
'width': newfile.thumbnail.width,
'height': newfile.thumbnail.height
}
}
return HttpResponse(json.dumps(results))
raise Http404
1👍
You can save the file and assign its path (relative to MEDIA_ROOT) to destination field manually.
thumb_path = 'uploads/1_small.jpg'
thumb_image_fit.save(os.path.join(MEDIA_ROOT, thumb_path), 'JPEG', quality=75)
newfile.thumbnail = thumb_path
Surely you’ll need to do all Django’s stuff manually – check if the file exists, modify name if it does, and so on.
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Source:stackexchange.com