19👍
You can access parameters from your request directly in your template if you activate django.core.context_processors.request in your settings. See https://docs.djangoproject.com/en/1.7/ref/templates/api/#django-core-context-processors-request
Then you can access parameters in your template directly. In your case you’ll need to filter page parameter. You could do something like this:
href="?page={{ data.next_page_number }}{% for key, value in request.GET.items %}{% if key != 'page' %}&{{ key }}={{ value }}{% endif %}{% endfor %}"
19👍
Another possible solution can be to construct parameters list in your view. Pros: you can use clean and expressive methods on QueryDict.
It will be look like this:
get_copy = request.GET.copy()
parameters = get_copy.pop('page', True) and get_copy.urlencode()
context['parameters'] = parameters
That’s it! Now you can use your context variable in template:
href="?page={{ paginator.next_page_number }}&{{ parameters }}"
See, code looks clean and nicely.
note: assumes, that your context contained in context dict and your paginator in paginator variable
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0👍
The easy way would be to include those variables in your template:
<a href="?var1={{var1}}&var2={{var2}}&page={{ data.next_page_number }}">next</a>
Just add var1 and var2 to your context.
That’s if the query string variables are originated from your backend. If they’re coming from the front-end/external, you could use something like How can I get query string values in JavaScript? in your template and either edit the template vars directly or pass the values to your backend.
0👍
Similar to YPCrumble’s answer, the following snippet works for me. But the template files could get pretty crowded when there are multiple parameters.
<a href="?p={{ page }}{% if search %}&search={{ search }}{% endif %}">{{ page }}</a>
Note that you must know the parameter names when apply this solution, so it may not fully satisfy your need.