No string-argument constructor/factory method to deserialize from string value

The error message “no string-argument constructor/factory method to deserialize from string value” typically occurs when you are trying to deserialize an object from a string value, but the object does not have a suitable constructor or factory method that takes a string argument.

When deserializing an object from a string value, the deserialization process relies on a constructor or factory method to create an instance of the object using the provided string value. However, if the object does not have a constructor or factory method that accepts a string argument, the deserialization process fails and throws the mentioned error.

Here is an example to illustrate the issue:

    
public class Person {
    private String name;
  
    public Person() {
        // Default constructor without any arguments
    }
  
    public Person(String name) {
        this.name = name;
    }
  
    public String getName() {
        return name;
    }
}
  
String jsonString = "{\"name\":\"John\"}";
ObjectMapper objectMapper = new ObjectMapper();
Person person = objectMapper.readValue(jsonString, Person.class);
    
  

In the above example, the Person class does not have a constructor or factory method that accepts a string argument. When trying to deserialize the JSON string into a Person object using readValue(jsonString, Person.class), the deserialization process fails and throws the “no string-argument constructor/factory method” error.

To resolve this issue, you have a few options:

  • Add a constructor or factory method to the object that accepts a string argument:
  •       
    public class Person {
        private String name;
    
        public Person() {
            // Default constructor without any arguments
        }
    
        public Person(String name) {
            this.name = name;
        }
    
        public String getName() {
            return name;
        }
    
        public static Person fromString(String jsonString) {
            // Create a new Person object from the provided string value
            // Parse the jsonString and set the necessary fields
            return new Person(parsedName);
        }
    }
    
    String jsonString = "{\"name\":\"John\"}";
    ObjectMapper objectMapper = new ObjectMapper();
    Person person = objectMapper.readValue(jsonString, Person.class);
          
        
  • If modifying the object is not an option, you can create a custom deserializer:
  •       
    public class PersonDeserializer extends StdDeserializer<Person> {
    
        public PersonDeserializer() {
            this(null);
        }
    
        public PersonDeserializer(Class<?> vc) {
            super(vc);
        }
    
        @Override
        public Person deserialize(JsonParser jp, DeserializationContext ctxt)
                throws IOException, JsonProcessingException {
            // Parse the jsonString and set the necessary fields
            return new Person(parsedName);
        }
    }
    
    String jsonString = "{\"name\":\"John\"}";
    ObjectMapper objectMapper = new ObjectMapper();
    SimpleModule module = new SimpleModule();
    module.addDeserializer(Person.class, new PersonDeserializer());
    objectMapper.registerModule(module);
    Person person = objectMapper.readValue(jsonString, Person.class);
          
        

Both of the above options provide a way to deserialize the object from the string value by either adding a suitable constructor or factory method, or by creating a custom deserializer to handle the deserialization process.

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