[Django]-Is it possible to pass query parameters via Django's {% url %} template tag?

A way to mix-up current parameters with new one:

{% url 'order_list' %}?office=foobar&{{ request.GET.urlencode }}

Modify your settings to have request variable:

from django.conf.global_settings import TEMPLATE_CONTEXT_PROCESSORS as TCP

TEMPLATE_CONTEXT_PROCESSORS = TCP + (
    'django.core.context_processors.request',
)

Use urlencode if the argument is a variable

<a href="{% url 'myview' %}?office={{ some_var | urlencode }}">

or else special characters like spaces might break your URL.

Documentation: https://docs.djangoproject.com/en/3.0/ref/templates/builtins/#urlencode

First, a silly answer:

{% url my-view-name %}?office=foobar

A serious anwser: No, you can’t. Django’s URL resolver matches only the path part of the URL, thus the {% url %} tag can only reverse that part of URL.

If your url (and the view) contains variable office then you can pass it like this:

{% url 'some-url-name' foobar %}

or like this, if you have more than one parameter:

{% url 'some-url-name' office='foobar' %}

Documentation: https://docs.djangoproject.com/en/3.1/ref/templates/builtins/#url

Tried all the above, nothing worked.
My system has:

• Python 3.8.10
• python3 -m django –version 4.0.3

Here’s what worked for me:
urls.py

urlpatterns = [
    path('', views.index, name='index'),
    path('single/', views.single, name='single'),
]

views.py

def single(request):
    url = request.GET.get('url')
    return HttpResponse(url)

Calling from .html file

<a href={% url 'single' %}?url={{url}} target="_self">

Broswer URL

http://127.0.0.1:8000/newsblog/single/?url=https://www.cnn.com/2022/08/16/politics/liz-cheney-wyoming-alaska-primaries/index.html

Try this:

{% url 'myview' office=foobar %}

It worked for me. It basically does a reverse on that link and applies the given arguments.