[Answered ]-In Django how to return an existing model instance when saving to database

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1👍

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There are a number of reasons why your save() method won’t work as written. (For one, the return value of save() isn’t used, so return found has no effect.)

But there’s no reason to try and reinvent this yourself: get rid of your custom save() and just use get_or_create():

def test_personne_is_the_same(self):
    p1, _ = Personne.objects.get_or_create(nom="Malcom X")
    p2, _ = Personne.objects.get_or_create(nom="Malcom X")
    self.assertEqual(p1, p2)
👤Kevin Christopher Henry

1👍

Django model gives a function called get_or_create which returns object and a flag which says created or not. i.e (obj, True or False).
So what you can do in save is.

found, created =  AudioFile.objects.get_or_create(nom=self.nom)
if created:
    super(Personne, self).save(*args, **kwargs)
return found

If this doenot work you can do 

try:
    found = AudioFile.objects.get(nom=self.nom)
except AudioFile.DoesNotExist:
    found = AudioFile(nom=self.nom)
    found.save()
super(Personne, self).save(*args, **kwargs)
return found

Also shouldnot your Personne inherit models.Model ?

UPDATE:

Basically if there is no model called AudioFile and you are not checking relation in Personne then next answer is sensible choice to test.

👤sagarchalise

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