144π
You can access the groups simply through the groups
attribute on User
.
from django.contrib.auth.models import User, Group
group = Group(name = "Editor")
group.save() # save this new group for this example
user = User.objects.get(pk = 1) # assuming, there is one initial user
user.groups.add(group) # user is now in the "Editor" group
then user.groups.all()
returns [<Group: Editor>]
.
Alternatively, and more directly, you can check if a a user is in a group by:
if django_user.groups.filter(name = groupname).exists():
...
Note that groupname
can also be the actual Django Group object.
273π
Your User object is linked to the Group object through a ManyToMany relationship.
You can thereby apply the filter method to user.groups.
So, to check if a given User is in a certain group ("Member" for the example), just do this :
def is_member(user):
return user.groups.filter(name='Member').exists()
If you want to check if a given user belongs to more than one given groups, use the __in operator like so :
def is_in_multiple_groups(user):
return user.groups.filter(name__in=['group1', 'group2']).exists()
Note that those functions can be used with the @user_passes_test decorator to manage access to your views :
from django.contrib.auth.decorators import login_required, user_passes_test
@login_required
@user_passes_test(is_member) # or @user_passes_test(is_in_multiple_groups)
def myview(request):
# Do your processing
For class based views, you might use UserPassesTestMixin
with test_func
method:
from django.contrib.auth.mixins import LoginRequiredMixin, UserPassesTestMixin
class MyView(LoginRequiredMixin, UserPassesTestMixin, View):
login_url = '/login/'
redirect_field_name = 'redirect_to'
def test_func(self):
return is_member(self.request.user)
Hope this help
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20π
If you donβt need the user instance on site (as I did), you can do it with
User.objects.filter(pk=userId, groups__name='Editor').exists()
This will produce only one request to the database and return a boolean.
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16π
If you need the list of users that are in a group, you can do this instead:
from django.contrib.auth.models import Group
users_in_group = Group.objects.get(name="group name").user_set.all()
and then check
if user in users_in_group:
# do something
to check if the user is in the group.
Update 2023
Looking at this solution 10 years later, Iβm pretty sure that I would NOT want to ever to fetch a whole list of users like this. Itβs something that would be problematic at scale. You would only want to fetch a list of users in a very specific use case where there were assurances that the list of users was going to remain small, or if you were just using the Django shell.
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11π
If a user belongs to a certain group or not, can be checked in django templates using:
{% if group in request.user.groups.all %}
"some action"
{% endif %}
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10π
You just need one line:
from django.contrib.auth.decorators import user_passes_test
@user_passes_test(lambda u: u.groups.filter(name='companyGroup').exists())
def you_view():
return HttpResponse("Since you're logged in, you can see this text!")
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8π
Use this:
{% for group in request.user.groups.all %}
{% if group.name == 'GroupName' %}
{% endif %}
{% endfor %}
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4π
I have similar situation, I wanted to test if the user is in a certain group. So, Iβve created new file utils.py where I put all my small utilities that help me through entire application. There, Iβve have this definition:
utils.py
def is_company_admin(user):
return user.groups.filter(name='company_admin').exists()
so basically I am testing if the user is in the group company_admin and for clarity Iβve called this function is_company_admin.
When I want to check if the user is in the company_admin I just do this:
views.py
from .utils import *
if is_company_admin(request.user):
data = Company.objects.all().filter(id=request.user.company.id)
Now, if you wish to test same in your template, you can add is_user_admin in your context, something like this:
views.py
return render(request, 'admin/users.html', {'data': data, 'is_company_admin': is_company_admin(request.user)})
Now you can evaluate you response in a template:
users.html
{% if is_company_admin %}
... do something ...
{% endif %}
Simple and clean solution, based on answers that can be found earlier in this thread, but done differently. Hope it will help someone.
Tested in Django 3.0.4.
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1π
Just in case if you wanna check userβs group belongs to a predefined group list:
def is_allowed(user):
allowed_group = set(['admin', 'lead', 'manager'])
usr = User.objects.get(username=user)
groups = [ x.name for x in usr.groups.all()]
if allowed_group.intersection(set(groups)):
return True
return False
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0π
In one line:
'Groupname' in user.groups.values_list('name', flat=True)
This evaluates to either True
or False
.
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0π
I have done it the following way. Seems inefficient but I had no other way in my mind:
@login_required
def list_track(request):
usergroup = request.user.groups.values_list('name', flat=True).first()
if usergroup in 'appAdmin':
tracks = QuestionTrack.objects.order_by('pk')
return render(request, 'cmit/appadmin/list_track.html', {'tracks': tracks})
else:
return HttpResponseRedirect('/cmit/loggedin')
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0π
User.objects.filter(username='tom', groups__name='admin').exists()
That query will inform you user : βtomβ whether belong to group βadmin β or not
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0π
I did it like this. For group named Editor
.
# views.py
def index(request):
current_user_groups = request.user.groups.values_list("name", flat=True)
context = {
"is_editor": "Editor" in current_user_groups,
}
return render(request, "index.html", context)
template
# index.html
{% if is_editor %}
<h1>Editor tools</h1>
{% endif %}
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