[Answered ]-In Django, how can I create a independent combobox that doesn't use the database?

by

1👍

✅

Your form is okay. If you are not going to persist data then you do not need to use Django models. The only thing you need to do is create a instance of this form and render it.

Suppose we create and app called myapp. There you have your files, such as forms, views, urls, etc.

myapp/views.py

from django.shortcuts import render, redirect
from myapp.forms import SimpleCombobox

def index(request):
    if request.method == "POST":
        form = SimpleCombobox(request.POST)
        if form.is_valid():
            print(form.cleaned_data)
            # Output Sample
            # {'favorite_colors': ['blue', 'green']}
            return redirect("index")

    else:
        form = SimpleCombobox()

    return render(request, "index.html", {"form": form})

myapp/urls.py

from django.urls import path
from myapp.views import index

urlpatterns = [
    path('', index, name='index')
]

Note that you can also use relative imports (e.g. from .forms import SimpleCombobox). Although in my example I am using absolute imports.

index.html

...
<body>
    <form method="post">
        {% csrf_token %}
        {{form}}
        <button type="submit">
            submit
        </button>
    </form>
</body>
...

Then include myapp.urls setup to the root urls.py:

from django.contrib import admin
from django.urls import path, include

urlpatterns = [
    path('admin/', admin.site.urls),
    path('', include('myapp.urls'))
]

If you have setup your templates correctly at settings.py (for instance):

TEMPLATES = [
    {
        ...
        'DIRS': [ BASE_DIR / 'templates' ],
        ...
    },
]

And have a running server, you should be good to go!

👤Niko

Leave a comment