[Answered ]-How to use slug to form urls

by

2👍

✅

Oh, there is serious problems with your views:

First:

class ListView(generic.ListView, slug, id)

should be

class ListView(generic.ListView)

see python inheritance.

Second:

slug and id must be class members of your view so you can redefine you view like this:

class ListView(generic.ListView):
   template_name = 'entertainment/index.html'
   context_object_name = 'latest_article_list'
   slug = None
   id = None

def get_queryset(self):

    return Entertainmentblog.objects.order_by('-posted')[:25]

Third:

Youre naming a derivate class as its parent. I don’t know the implications of doing this, but surely, isn’t a good practice.

Finally:

The error you’re getting is becouse the view returned by views.DetailView.as_view() (remember DetailView is your derived class) don’t receives the arguments you are passing through url. Check your url, I can see in the error that is complaining about and argument (u'what-is-happening',) but there is no id. It should be something like, for example, (u'what-is-happening', '4')

👤Raydel Miranda

Leave a comment