๐:0
I hope you do assign $result
somewhere. There does not seem to be any query.
Then there is a โ;โ missing after your echo
statement in the while
structure.
Also, your whole data setup does not make any sense: why would you overwrite $set1
and $set2
again and again, just to end up using just the last results.
I assume (by your naming) you want the sets to hold multiple values. That would be achieved by initializing them as arrays first and then pushing each rows values to them:
$set1[] = $row['standName'];
$set2[] = $row['currentQty'];
At least this way you would actually end up with sets of data.
Finally, have a look at how Chart.js works for Pie charts: http://www.chartjs.org/docs/#doughnut-pie-chart-example-usage
Handing over something like $row['standName']
(presumably a string) as a data point value (numeric) does not mak any sense.
Since it is not at all clear, what you are trying to do here, I will go out on a limb:
<?php
...
$data = array();
$colors = array("#F38630","#E0E4CC");
$i=0;
while ($row = mysql_fetch_assoc($result)) {
echo $row['standName'] . ' | ' . $row['currentQty'] . ' %' . "\n";
$data[] = array(
'value' => $row['currentQty'],
'label' => $row['standName'],
'color' => $colors[$i%2], // just alternating colors
);
$i++;
}
$pieData = jseon_encode($data);
?>
<script type="text/javascript" src="js/Chart.min.js"></script>
<script>
var myPie = new Chart(document.getElementById("canvas").getContext("2d")).Pie(<?php echo $pieData; ?>);
</script>