0๐
โ
You could use reduce
method and return one object with object as values.
const data = [{"channel":"A","mkp":"ABC","qtd":6,"total":2938.2,"data":"2019-02-16","time":"22:30:40"},{"channel":"C","mkp":"DEF","qtd":1545,"total":2127229.64,"data":"2019-02-20","time":"17:19:49"},{"channel":"C","mkp":"JKL","qtd":976,"total":1307328.37,"data":"2019-02-20","time":"17:19:53"},{"channel":"U","mkp":"PQR","qtd":77,"total":98789.87,"data":"2019-02-20","time":"16:12:31"},{"channel":"U","mkp":"STU","qtd":427,"total":433206.62,"data":"2019-02-20","time":"17:04:27"}]
const res = data.reduce((r, {channel, qtd, total, data, time}) => {
const dateTime = `${data} ${time}`
if(!r[channel]) r[channel] = {qtd, total, dateTime}
else {
r[channel].total += total
r[channel].qtd += qtd;
r[channel].dateTime = dateTime
}
return r;
}, {})
console.log(res)
0๐
You an use reduce
to group the values based on channel
like this:
const input = [{"channel":"A","mkp":"ABC","qtd":6,"total":2938.2,"data":"2019-02-16","time":"22:30:40"},{"channel":"C","mkp":"DEF","qtd":1545,"total":2127229.64,"data":"2019-02-20","time":"17:19:49"},{"channel":"C","mkp":"JKL","qtd":976,"total":1307328.37,"data":"2019-02-20","time":"17:19:53"},{"channel":"U","mkp":"PQR","qtd":77,"total":98789.87,"data":"2019-02-20","time":"16:12:31"},{"channel":"U","mkp":"STU","qtd":427,"total":433206.62,"data":"2019-02-20","time":"17:04:27"}]
const merged = input.reduce((acc, { channel, qtd, total, data, time }) => {
acc[channel] = acc[channel] || [{ qtd: 0, total: 0, dateTime:'' }];
const group = acc[channel][0];
group.qtd += qtd;
group.total += total;
const dateTime = `${data} ${time}`
if(dateTime > group.dateTime)
group.dateTime = dateTime;
return acc;
}, {})
console.log(merged)
Source:stackexchange.com