[Django]-How to get the name of current app within a template?

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23đź‘Ť

âś…

There’s a way to obtain an app name for a current request.
First, in your project’s urls.py, considering your app is called 'main':

#urls.py
url(r'^', include('main.urls', app_name="main")),

Then, a context processsor:

#main/contexts.py
from django.core.urlresolvers import resolve
def appname(request):
    return {'appname': resolve(request.path).app_name}

Don’t forget to enable it in your settings:

#settings.py
TEMPLATE_CONTEXT_PROCESSORS = (
"django.core.context_processors.request",
"main.contexts.appname",)

You can use it in your template like any other variable: {{ appname }}.

👤Alex Parakhnevich

28đź‘Ť

Since Django 1.5 there is a “resolver_match” attribute on the request object.

https://docs.djangoproject.com/en/dev/ref/request-response/

This contains the matched url configuration including “app_name”, “namespace”, etc.

https://docs.djangoproject.com/en/2.2/ref/urlresolvers/#django.urls.ResolverMatch

The only caveat is that it is not populated until after the first middleware passthrough, so is not available in process_request functions of middleware. However it is available in middleware process_view, views, and context processors. Also, seems like resolver_match is not populated in error handlers.

Example context processor to make available in all templates:

def resolver_context_processor(request):
    return {
        'app_name': request.resolver_match.app_name,
        'namespace': request.resolver_match.namespace,
        'url_name': request.resolver_match.url_name
    }
👤Ken Colton

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