[Fixed]-How to exclude some indexes in a python loop?

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1👍

✅

l = [ [ 1, "EEBC92F4-DA8C-4B58-8730-3119F6B1C045", 1, 1386882230, "399231", 1386882230, "399231", "{\n}", "2010", "NON-HISPANIC BLACK", "MALE", "HUMAN IMMUNODEFICIENCY VIRUS DISEASE", "297", "5" ],
    [ 2, "84C91A4A-19E2-4AD2-9493-17B84707CA4E", 2, 1386882230, "399231", 1386882230, "399231", "{\n}", "2012", "NON-HISPANIC BLACK", "MALE", "INFLUENZA AND PNEUMONIA", "2011", "3" ]]

#get index of the year
l[0].index('2010') #8
l[1].index('2012') #8

In case you only want to print you can do:

for x in l:
    for el in x[8:]:
        print el

which gives you the following output:

2010
NON-HISPANIC BLACK
MALE
HUMAN IMMUNODEFICIENCY VIRUS DISEASE
297
5
2012
NON-HISPANIC BLACK
MALE
INFLUENZA AND PNEUMONIA
2011
3

Not fully sure whether that is what you want but you wrote that you need all the information after the respective years (“I’m referring about all the information after the year in every row.”, your reply to James in the comments) so you could first extract these elements and store them in a new list (in case you want to do something else with them except of printing): 

lmod = [x[8:] for x in l]

lmod then looks like this:

[['2010',
  'NON-HISPANIC BLACK',
  'MALE',
  'HUMAN IMMUNODEFICIENCY VIRUS DISEASE',
  '297',
  '5'],
 ['2012',
  'NON-HISPANIC BLACK',
  'MALE',
  'INFLUENZA AND PNEUMONIA',
  '2011',
  '3']]

This can now be printed as you did it:

for sl in lmod:
   for el in sl:
       print el

Output:

2010
NON-HISPANIC BLACK
MALE
HUMAN IMMUNODEFICIENCY VIRUS DISEASE
297
5
2012
NON-HISPANIC BLACK
MALE
INFLUENZA AND PNEUMONIA
2011
3

Is that what you were looking for?

👤Cleb

0👍

You didn’t really give a great example, but you can use a generator:

filteredList = (x for x in list if int(x[8]) >= 2010)
for a in filteredList:
    for b in a:
        print b

Or, you can write it more directly:

for a in (x for x in list if int(x[8]) >= 2010):
    for b in a:
        print b

Though, you might want your “records” here to be dicts instead of lists.

👤rlbond

0👍

for a in mylist:
    if int(a[8]) > 2009:
        for b in a:
            print b,
        print

This goes through each item in mylist (renamed from the list that masks the built-in), checks if the element at index 8 is greater than 2009, and then prints out the item’s elements separated by a single space. If you want more control over the output, use string formatting.

👤TigerhawkT3

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