[Django]-How to customize the auth.User Admin page in Django CRUD?

by

87👍

✅

I finally did like this in my admin.py file :

from django.contrib.auth.admin import UserAdmin
from django.contrib.auth.models import User

UserAdmin.list_display = ('email', 'first_name', 'last_name', 'is_active', 'date_joined', 'is_staff')

admin.site.unregister(User)
admin.site.register(User, UserAdmin)
👤Natim

24👍

Another way to do this is extending the UserAdmin class.

You can also create a function to put on list_display

from django.contrib.auth.admin import UserAdmin
from django.contrib.auth.models import User

class CustomUserAdmin(UserAdmin):
    def __init__(self, *args, **kwargs):
        super(UserAdmin,self).__init__(*args, **kwargs)
        UserAdmin.list_display = list(UserAdmin.list_display) + ['date_joined', 'some_function']

    # Function to count objects of each user from another Model (where user is FK)
    def some_function(self, obj):
        return obj.another_model_set.count()


admin.site.unregister(User)
admin.site.register(User, CustomUserAdmin)
👤Fernando Freitas Alves

1👍

In admin.py

Import UserAdmin

from django.contrib.auth.admin import UserAdmin

Put which fields you need:

UserAdmin.list_display = ('email','is_active')  # Put what you need

Thats all! It works with Django3

👤devugur

-3👍

Assuming that your user class is User and your subscription date field is subscription_date, this is what you need to add on your admin.py

class UserAdmin(admin.ModelAdmin):
    list_display = ('subscription_date',)

admin.site.register(User, UserAdmin)
👤Joshua Partogi

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