1đź‘Ť
I found a solution in: http://davedash.com/2010/02/11/retrieving-elements-in-a-specific-order-in-django-and-mysql/ it’s suited me perfectly.
ids = [a_list, of, ordered, ids]
addons = Addon.objects.filter(id__in=ids).extra(
select={'manual': 'FIELD(id,%s)' % ','.join(map(str,ids))},
order_by=['manual'])
This code do something similiar to MySQL “ORDER BY FIELD”.
1đź‘Ť
Would have been nice to have this feature in SQL – sorting by a known list of values.
Instead, what you could do is:
obj_oportunidades=Opor.objects.in_bulk(list_ids).values()
all_opor = []
for o in obj_oportunidades:
print o
all_opor.append(o)
for i in list_ids:
if i in all_opor:
print all_opor.index(i)
Downside is that you have to get all the result rows first and store them before getting them in the order you want. (all_opor
could be a dictionary above, with the table records stored in the values and the PKeys as dict keys.)
Other way, create a temp table with (Sort_Order
, Pkey
) and add that to the query:
Sort_Order PKey
1 31189
2 31191
...
So when you sort on Sort_Order and Opor.objects, you’ll get Pkeys it in the order you specify.
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1đź‘Ť
This guy: http://blog.mathieu-leplatre.info/django-create-a-queryset-from-a-list-preserving-order.html
Solved the problem for both MySQL and PostgreSQL!
If you are using PostgreSQL go to that page.
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