[Django]-How do I use the The login_required decorator in my URL?

by

34👍

✅

To use decorators in urls.py you need use real functions instead of their names:

from django.contrib.auth.decorators import login_required
import django.views.generic.date_based as views

urlpatterns = patterns('',
    (r'^$', login_required(views.archive_index), link_info_dict,
            'coltrane_link_archive_index'),
    ...
👤catavaran

7👍

In Django 1.11+, at least, you can do it directly as you want. For example:

# urls.py

from django.contrib.auth.decorators import login_required

urlpatterns = [
    # Home path
    path('', login_required(TemplateView.as_view(template_name='core/home.html')), name='home'),
    # Another paths
    # ...
]

In this case, each time you try to enter the homepage, you must be logged in, otherwise you will go to the login screen and then return to your homepage.

👤cjadeveloper

1👍

you can use decorate_url

http://github.com/vorujack/decorate_url

pip install decorate_url
👤vorujack

0👍

Those docs are for generic views, which work slightly differently than custom views. Normally login_required is used to decorate a view; if you want to use it within a urlconf then you’ll need to write a lambda to wrap the view.

👤Ignacio Vazquez-Abrams

0👍

For Django v4.1.4,
In addition to @catavaran’s answer, when you are using a Custom Login URL instead of django’s default login, then you need to give the custom url to the login_url parameter.

urls.py

from django.contrib.auth.decorators import login_required

urlpatterns = [
    path('', login_required(TemplateView.as_view(template_name='app_name/template_name.html'),login_url='/custom_login_url/'), name='path-name'),
]
👤Yusuf

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