137👍
Have you tried just running the task from the Django shell? You can use the .apply
method of a task to ensure that it is run eagerly and locally.
Assuming the task is called my_task
in Django app myapp
in a tasks
submodule:
$ python manage.py shell
>>> from myapp.tasks import my_task
>>> eager_result = my_task.apply()
The result instance has the same API as the usual AsyncResult
type, except that the result is always evaluated eagerly and locally and the .apply()
method will block until the task is run to completion.
42👍
If you means just trigger a task when the condition is not satisfied, for example, the periodic time not meet. You can do it in two steps.
1.Get your task id.
You can do it by typing.
celery inspect registered
You will see something like app.tasks.update_something
.
If nothing, it is probably that celery
was not started. Just run it.
2.Run the task with celery call
celery call app.tasks.update_something
For more details, just type
celery --help
celery inspect --help
celery call --help
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11👍
I think you’ll need to open two shells: one for executing tasks from the Python/Django shell, and one for running celery worker
(python manage.py celery worker
). And as the previous answer said, you can run tasks using apply()
or apply_async()
I’ve edited the answer so you’re not using a deprecated command.
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