[Django]-Get the latest record with filter in Django

See the docs from django:
https://docs.djangoproject.com/en/dev/ref/models/querysets/#latest

You need to specify a field in latest(). eg.

obj= Model.objects.filter(testfield=12).latest('testfield')

Or if your model’s Meta specifies get_latest_by, you can leave off the field_name argument to earliest() or latest(). Django will use the field specified in get_latest_by by default.

last() latest()

Usign last():

ModelName.objects.last()

using latest():

ModelName.objects.latest('id')

latest is really designed to work with date fields (it probably does work with other total-ordered types too, but not sure). And the only way you can use it without specifying the field name is by setting the get_latest_by meta attribute, as mentioned here.

obj= Model.objects.filter(testfield=12).order_by('-id')[:1] is the right solution

obj = Model.objects.filter(testfield=12).order_by('id').latest('id')

1. Filter based on what field you need – in this case is testfield

Model.objects.filter(testfield=12)

2. In order to get the latest record, first you need to sort the queryset. So that it knows to return the last record based on a criteria.

Now, order the results base on your primary key – most of the times the pk=id

Model.objects.filter(testfield=12).order_by(‘id’)

https://docs.djangoproject.com/en/4.0/ref/models/querysets/#order-by

By default, results returned by a QuerySet are ordered by the ordering tuple given by the ordering option in the model’s Meta. You can override this on a per-QuerySet basis by using the order_by method.

3. After you have the queryset and you have sorted it. Get the latest based on the criteria you need – in this case is the id.

Model.objects.filter(testfield=12).order_by(‘id’).latest(‘id’)

You can do comparison with this down here.

latest('created') is same as order_by('-created').first()
Please correct me if I am wrong