2👍
Flatten the array first. Be careful of using && item.id
inside the mapper because that’ll mean that falsey IDs (like 0, which is a reasonable starting number in some schemes) will be excluded.
const items=[{id:1,name:"banana",selected:!0},{id:2,subItems:[{id:"2a",name:"apple",selected:!0},{id:"2b",name:"orange",selected:!1}]},{id:3,name:"watermalon",selected:!0},{id:4,name:"pear",selected:!1}];
const output = items
.flatMap(item => [item].concat(item.subItems ?? []))
.filter(item => item.selected)
.map(item => item.id);
console.log(output);
1👍
You can recursively traverse all the items and select the items that have selected
set to true
.
const items = [
{ id: 1, name: "banana", selected: true },
{
id: 2,
subItems: [
{ id: "2a", name: "apple", selected: true },
{ id: "2b", name: "orange", selected: false },
],
},
{ id: 3, name: "watermalon", selected: true },
{ id: 4, name: "pear", selected: false },
];
function getSelectedItems(items, selectedItems = []) {
for (let item of items) {
if (item.subItems) {
getSelectedItems(item.subItems, selectedItems);
} else if (item.selected) {
selectedItems.push(item.id);
}
}
return selectedItems;
}
console.log(getSelectedItems(items));
0👍
let newArray = [];
items.forEach(i=>{
if(i.selected){
newArray.push(i.id)
}
if(i.subItems){
i.subItems.forEach(j=>{
if(j.selected){
newArray.push(j.id)
}
})
}
});
so this is bit lengthy. with 2 map loops
0👍
You can do:
const items=[{id:1,name:"banana",selected:!0},{id:2,subItems:[{id:"2a",name:"apple",selected:!0},{id:"2b",name:"orange",selected:!1}]},{id:3,name:"watermalon",selected:!0},{id:4,name:"pear",selected:!1}]
const output = items
.reduce((a, c) => [...a, c, ...(c.subItems || [])], [])
.filter(o => o.selected)
.map(({ id }) => id)
console.log(output)
0👍
Checking if a subItems
array exsist in the item and recusively calling a function to extract selected Items will solve the issue.
function extractSubItems (items){
var selectItemsId = [];
selectItemsId = selectItemsId + items.map(item => {
if (item.selected===true){
return item.id;
}
if (item.subItems){
return extractSubItems(item.subItems);
}
}).filter(Boolean);
return selectItemsId
}
0👍
You can use Array#reduce
in a nested fashion as follows:
const items = [ { id: 1, name: 'banana', selected: true, }, { id: 2, subItems: [ { id: '2a', name: 'apple', selected: true, }, { id: '2b', name: 'orange', selected: false, }, ], }, { id: 3, name: 'watermalon', selected: true, }, { id: 4, name: 'pear', selected: false, }, ],
output = items
.reduce(
(prev, {id,selected,subItems}) =>
subItems ?
selected ?
[...prev,id,...subItems.reduce( (p, {id:ID,selected:SEL}) => SEL ? [...p,ID] : p, [] )] :
[...prev,...subItems.reduce( (p, {id:ID,selected:SEL}) => SEL ? [...p,ID] : p, [] )] :
selected ?
[...prev,id] :
prev, []
);
console.log( output )
0👍
1 – Loop through items array
2 – if there is no subItems array then find the id of the item using condition
3 – if there is a subItems array then loop through that and find the id using condition
const result = []
items.map(item=>{
item.subItems ?
item.subItems.map(sub=>{
sub.selected && result.push(sub.id)
})
: item.selected && result.push(item.id)
})
console.log(result) // [1, "2a", 3]
0👍
This also works:
var ids = [
... items.filter(
it => it.selected || (it.subItems && it.subItems.some( sub => sub.selected ))
)
.map( it =>
it.subItems
? it.subItems.filter( it_sub => it_sub.selected ).map( it_sub => it_sub.id )
: [it.id]
)
].flat()
0👍
With resursive of subItems :
const items=[
{id:1,name:"banana",selected:!0},
{id:2,subItems:
[
{id:"2a",name:"apple",selected:!0},
{id:"2b",name:"orange",selected:!1},
{id:"2c",subItems:
[
{id:"2c1",name:"apple1",selected:!0},
{id:"2c1",name:"orange1",selected:!1}
]
},
]
},
{id:3,name:"watermalon",selected:!0},
{id:4,name:"pear",selected:!1}
];
const getSubItem = (obj) => {
let result = !obj.hasOwnProperty('subItems') ? [obj] : obj.subItems.reduce((res, item) => {
return res.concat(getSubItem(item))
}, [])
return result.filter(item => item.selected)
}
const result = items.reduce((res, item) => {
let subItem = getSubItem(item)
return res.concat(getSubItem(item))
}, [])
console.log(result)