4๐
โ
You can replace the underscore sequences with the appropriate characters based on their position within the input string:
function convertDate(date) {
return date.replace(/_+/g, (_, n) => (n < 10) ? "/" : (n > 10) ? ":" : " ");
}
console.log(convertDate("DD_MM_YYYY_hh_mm__ss"));
Or slightly simpler:
function convertDate(date) {
let n = 0; return date.replace(/_+/g, () => "// ::"[n++]);
}
console.log(convertDate("DD_MM_YYYY_hh_mm__ss"));
๐คMike D Sutton
3๐
One way:
const str = '18_03_2022_12_21_34'
// to string
const res = str.split('_')
const r = res.slice(0, 3).join('/') + ' ' + res.slice(-3).join(':')
console.log(r)
// or to date
console.log(new Date(res.slice(0, 3).join('/').split('/').reverse().join('/') + ' ' + res.slice(-3).join(':')))
๐คNikola Pavicevic
2๐
Vue Filter
Code:
Vue.filter('stringTodateTime', function ( dateTimeString ) {
if (!dateTimeString) return ''
return dateTimeString.replace(/_+/g, (_, n) => (n < 10) ? "/" : (n > 10) ? ":" : " ");
})
Usage:
{{ 12_04_2021_12_59_34 | stringTodateTime }}
๐คGMKHussain
Source:stackexchange.com