[Fixed]-For a Charfield with choices, how to use the human readable name in list_display through a foreignkey?

From the docs, and for the field val,

class ModelAAdmin(ModelAdmin):
    list_display = ['get_val_display']

This should do the job.

[EDIT by OP]
I didn’t succeed to make it work like this but this kind of method was a really good suggestion. Here is how I used this get_FOO_display() method (and it worked like a charm).

I only modified my ModelA.val() method :

def val(self):
    return self.model_b.get_value_display()