Flutter showdialog async

flutter showdialog async

In Flutter, the showDialog function is used to display a dialog box on the screen. It is an asynchronous operation, meaning that it returns a Future. You can use the async/await keywords to work with the Future and write asynchronous code.

Here is an example of how to use the showDialog function with async/await:

<button onPressed="showAlertDialog">
  Show Dialog
</button>

void showAlertDialog() async {
  final result = await showDialog(
    context: context,
    builder: (BuildContext context) {
      return AlertDialog(
        title: Text("Dialog Title"),
        content: Text("Dialog Content"),
        actions: <Widget>[
          FlatButton(
            child: Text("Cancel"),
            onPressed: () {
              Navigator.of(context).pop(false);
            },
          ),
          FlatButton(
            child: Text("OK"),
            onPressed: () {
              Navigator.of(context).pop(true);
            },
          ),
        ],
      );
    },
  );

  // Use the result returned by showDialog
  if (result) {
    print("User clicked OK");
  } else {
    print("User clicked Cancel");
  }
}

The above example shows a Flutter button. When pressed, it invokes the showAlertDialog function. Inside this function, showDialog is called with the context and a builder function. The builder function returns an AlertDialog widget, which is then displayed on the screen.

The showDialog function returns a Future that resolves to the result of the dialog (e.g., true if the user clicks OK, or false if the user clicks Cancel). By using await with the showDialog function call, the execution of the code is paused until the dialog is closed.

Once the dialog is closed, the value returned by the dialog (stored in the result variable) can be used in further logic. In this example, if the user clicks OK, the message "User clicked OK" is printed, and if the user clicks Cancel, the message "User clicked Cancel" is printed.