[Django]-Extract only values without key from QuerySet and save them to list

You can use values_list(…) ^[Django-doc] instead, and specify flat=True, like:

def get(self, request, format=None):
    labels = list(Temperature.objects.using('sensors').values_list('time', flat=True)) 
    temp_values = list(Temperature.objects.using('sensors').values_list('value', flat=True))
    # ...

but the above is not safe. A queryset is – unless you specify it – unordered. That means that two queries can result in data that does not "match" in the sense that the first time value does not per se corresponds to the first value value, although this might be atypical behavior (in some/most database systems), you typically never want this to happen. It also here results in two queries, which is not efficient.

You can first fetch the values, and then use maps (or zip) to make a transpose, like:

from operator import itemgetter

def get(self, request, format=None):
    qs = Temperature.objects.using('sensors').values_list('time', 'value')
    labels = list(map(itemgetter(0), qs))
    temp_values = list(map(itemgetter(1), qs))
    # ...