[Answered ]-Even though its a class why is AttributeError: 'function' object has no attribute 'as_view'

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1👍

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You can not use the @login_required decorator [Django-doc]: this decorator returns a function, but even using the function will not work: the decorator simply can not handle a class.

For class-based views, you use the LoginRequiredMixin [Django-doc]:

from django.contrib.auth.mixins import LoginRequiredMixin

class UpdateActiveStatus(LoginRequiredMixin, UpdateView):
    model = FutsalTimeline
    form_class = UpdateActiveStatus
    template_name = 'timeline.html'
    success_url = reverse_lazy('timeline')
    login_url = '/admin/'
👤willeM_ Van Onsem

0👍

I think the issue is generated for the decorator. Just change it like ->

@method_decorator(login_required, name='dispatch')
class UpdateActiveStatus(UpdateView):
    model = FutsalTimeline
    form_class = UpdateActiveStatus
    template_name = 'timeline.html'
    success_url = reverse_lazy('timeline')

You can find the doc here

  • But you should use the Mixin classes. With Mixin class It will look like

      from django.contrib.auth.mixins import LoginRequiredMixin
  class UpdateActiveStatus(LoginRequiredMixin, UpdateView):
      model = FutsalTimeline
      form_class = UpdateActiveStatus
      template_name = 'timeline.html'
      success_url = reverse_lazy('timeline')

You can find the doc here

👤Almabud

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