[Fixed]-Django rest framework: automatically create a url for each field of a model

You might be able to do that using a custom viewset route.

You have this:

class ModelViewSet(ModelViewSet):

    @list_route()
    def sample_field(self, request):
        desired_field = request.data.get('field', None)
        if not desired_field:
            return response # pseudocode

        values = Model.objects.all().values_list(desired_field, flat=True)
        # serialize this for returning the response
        return Response(json.dumps(values))  # this is an example, you might want to do something mode involved

You will be able to get this from the url:

/api/model/sample_field/?field=foo

This extra method on the viewset will create a new endpoint under the samples endpoint. Since it’s a list_route, you can reach it using /sample_field.

So following your code, it would be:

mysite.com/sample/sample_field/?field='year'

for example.

There are many interesting details in your question, but with this sample I think you might able to achieve what you want.