12๐
โ
I think it would be better to create your own url endpoint that maps to a view which makes a request to the external API.
# urls.py
url(r'^external-api/$', external_api_view)
# views.py
import requests
import time
from rest_framework import status
from rest_framework.response import Response
MAX_RETRIES = 5 # Arbitrary number of times we want to try
def external_api_view(request):
if request.method == "GET":
attempt_num = 0 # keep track of how many times we've retried
while attempt_num < MAX_RETRIES:
r = requests.get("https://example.com/consumers", timeout=10)
if r.status_code == 200:
data = r.json()
return Response(data, status=status.HTTP_200_OK)
else:
attempt_num += 1
# You can probably use a logger to log the error here
time.sleep(5) # Wait for 5 seconds before re-trying
return Response({"error": "Request failed"}, status=r.status_code)
else:
return Response({"error": "Method not allowed"}, status=status.HTTP_400_BAD_REQUEST)
Just an example. You can do it as a class-based view as well.
๐คThomas Jiang
0๐
Whatever you are trying to achieve, this code will not work.
Firstly, ?P<name>
construct is just a way to give a symbolic name to a group. And it does not accept characters โ.โ, โ/โ and โ)โ. So correct name would be something like ?P<consumer_id>
.
Secondly, even after you correct mistakes in the regular expression (like this, for example r'^(?P<consumer_id>[0-9]+$)/'
), it will just match any URL like YOURDOMAIN.COM/<integer_number>/
.
I suggest you learn how regular expressions work in Python first.
๐คAndriy Makukha
Source:stackexchange.com