[Fixed]-Django model choice option as a multi select box

by

12👍

✅

Can a Car have multiple colors? In that case color ought to be a many to many relationship rather than a CharField. If on the other hand you want to do something like Unix permissions (i.e. Red + Blue, Red + Blue + Green etc.) then assign numeric values of to each of them and make color an integer field.

Update

(After reading comment) You can use a custom form to edit your model in Admin instead of the default ModelForm. This custom form can use a multiple choice widget that lets users select multiple colors. You can then override the clean() method of the form to return a suitably concatenated value (‘RB’ etc.).

Update 2

Here is some code:

First, remove the choices from the model field. Also increase its maximum size to 2. We don’t want choices here – if we do, then we’ll have to add a choice for each combination of colors. 

class Car(models.Model):
    ...
    color= models.CharField(max_length=2)

Second add a custom ModelForm to use in admin app. This form will override color and instead declare it as a multiple choice field. We do need choices here.

COLORS= (
    ('R', 'Red'),
    ('B', 'Yellow'),
    ('G', 'White'),
)

class CarAdminForm(ModelForm):
    color = forms.MultipleChoiceField(choices = COLORS)

    class Meta:
        model = Car

    def clean_color(self):
        color = self.cleaned_data['color']
        if not color:
            raise forms.ValidationError("...")

        if len(color) > 2:
            raise forms.ValidationError("...")

        color = ''.join(color)
        return color

Note that I have added only a couple of validations. You may want more and/or customize the validations.

Finally, register this form with admin. Inside your admin.py:

class CarAdmin(admin.ModelAdmin):
    form = CarAdminForm

admin.site.register(Car, CarAdmin)
👤Manoj Govindan

7👍

I’ve constructed a complete working example with meaningful models. It works perfect. I’ve tested it on Python 3.4.x and Django 1.8.4.
At first I run admin panel and create records for each option in Thema model

models.py

from django.db import models

class Author(models.Model):
    fname = models.CharField(max_length=50)
    lname = models.CharField(max_length=80)

    def __str__(self):
        return "{0} {1}".format(self.fname, self.lname)


class Thema(models.Model):
    THEME_CHOICES = (
        ('tech', 'Technical'),
        ('novel', 'Novel'),
        ('physco', 'Phsycological'),
    )
    name = models.CharField(max_length=20,choices=THEME_CHOICES, unique=True)

    def __str__(self):
        return self.name

class Book(models.Model):

    name = models.CharField(max_length=50)
    author = models.ForeignKey(Author)
    themes = models.ManyToManyField(Thema)

    def __str__(self):
        return "{0} by {1}".format(self.name,self.author)

forms.py

from django import forms

from .models import *

class BookForm(forms.ModelForm):
    themes = forms.ModelMultipleChoiceField(queryset=Thema.objects, widget=forms.CheckboxSelectMultiple(), required=False)

admin.py

from django.contrib import admin

from .models import *
from .forms import *

@admin.register(Author)
class AuthorAdmin(admin.ModelAdmin):
    pass


@admin.register(Book)    
class BookAdmin(admin.ModelAdmin):
    form = BookForm


@admin.register(Thema)
class ThemaAdmin(admin.ModelAdmin):
    pass
👤Serjik

1👍

Use a separate table with colors (Red, Blue, Green), and, as you said, add a many to many relationship ?
Choice type is not multiple choice, only a string with added UI and checkings.

Or, generate procedurally your choices with itertools.combinations, example: 

choices = zip(
  [''.join(x) for x in itertools.combinations(['','B','R','G'],2)],
  [' '.join(x) for x in itertools.combinations(['','Blue','Red','Green'],2)],
)

 # now choices = [(' Blue', 'B'), (' Red', 'R'), (' Green', 'G'), ('Blue Red', 'BR'), ('Blue Green', 'BG'), ('Red Green', 'RG')]
👤makapuf

1👍

For colors tuple, if you use integers instead of chars, you may use commaseparatedintegerfield for your model.
But Do not forget, commaseparatedintegerfield is a database level structure,so your DBMS must support it.

Documentation link…

👤Mp0int

0👍

The easiest way I found (just I use eval() to convert string gotten from input to tuple to read again for form instance or other place)

This trick works very well

#model.py
class ClassName(models.Model):
    field_name = models.CharField(max_length=100)

    def __init__(self, *args, **kwargs):
        super().__init__(*args, **kwargs)
        if self.field_name:
            self.field_name= eval(self.field_name)



#form.py
CHOICES = [('pi', 'PI'), ('ci', 'CI')]

class ClassNameForm(forms.ModelForm):
    field_name = forms.MultipleChoiceField(choices=CHOICES)

    class Meta:
        model = ClassName
        fields = ['field_name',]

#view.py
def viewfunction(request, pk):
    ins = ClassName.objects.get(pk=pk)

    form = ClassNameForm(instance=ins)
    if request.method == 'POST':
        form = form (request.POST, instance=ins)
        if form.is_valid():
            form.save()
            ...
👤younesfmgtc

0👍

Django models come with JSONField() which you could use to serialize the list of integer values and later deserialize it into a list. List of integers are your colors.

https://docs.djangoproject.com/en/4.0/ref/models/fields/#django.db.models.JSONField

👤Sher Sanginov

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