[Django]-Django: How to Convert QuerySet into String

by

6👍

{{top_post}} is a query set (slicing a queryset also produces a queryset), so it should display that. When you loop over the queryset, as you do over latest, you display the objects inside.

{{top_post.0}} would give you the object top_post contains.

Alternatively you can use

top_post = Post.objects.filter(category='1').first()

to get the object directly.

👤NS0

1👍

You should implement the __str__ method in the Post model where you define what to print.
Moreover you should .get instead of .filter if you expect one object to be returned.

👤Zahraa Hmayed

0👍

Convert it into list

def 
return(Post.objects.filter(category='1').first)
👤user12741426

0👍

to solve it you can use nested loops (A loop in other loop)

👤Sahil Asopa

0👍

If you are using filter then I am assuming you want more than one value else use the get method.
You can convert the queryset into a list and then play around the list.

top_post = list(Post.objects.filter(category='1')[:1])[0]

Now top_post will give the first object in the list.

👤shubham suroshe

0👍

Just to pile on to last bit about getting the actual value out of the QuerySet objects. This is what I do.

list_of_things = TableName.objects.all().values_list('thing', flat=True)

values_list lets me select what column(s) to return and flat=True extracts (for lack of a better term) each column as an object, thus loading up the list.

👤Dilapidus

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