-3👍
Okay, apparently, there’s no way to do such thing with ORM only.
If you have to do it, you have to use .extra() to execute needed SQL-statement (if you are using SQL database, of course)
7👍
I’m late to the party, but here you go:
Doggy.objects.values('color', 'name').annotate(Count('pk'))
This will give you results that have a count of how many of each Doggy you have grouped by color and name.
2👍
If you’re looking for Doggy’s of a certain colour – you’d do something like.
Doggy.objects.filter(color='blue')
If you want to find Doggys based on the colour of the current Doggy
def GetSimilarColoredDoggys(self):
return Doggy.objects.filter(color=self.color)
The same would go for names:-
def GetDoggysWithSameName(self):
return Doggy.objects.filter(color=self.name)
- [Django]-Why does Paypal retry IPN when using django-paypal
- [Django]-Encode ImageField in base64 and store it in DB instead of path of the image
- [Django]-How can I use SearchRank in a Django model field?
2👍
You can use itertools.groupby() for this:
import operator
import itertools
from django.db import models
def group_model_by_attr(model_class, attr_name):
assert issubclass(model_class, models.Model), \
"%s is not a Django model." % (model_class,)
assert attr_name in [field.name for field in Event._meta.fields], \
"The %s field doesn't exist on model %s" % (attr_name, model_class)
all_instances = model_class.objects.all().order_by(attr_name)
keyfunc = operator.attrgetter(attr_name)
return [{k: list(g)} for k, g in itertools.groupby(all_instances, keyfunc)]
grouped_by_color = group_model_by_attr(Doggy, 'color')
grouped_by_name = group_model_by_attr(Doggy, 'name')
grouped_by_color
(for example) will be a list of dicts like [{'purple': [doggy1, doggy2], {'pink': [doggy3,]}]
where doggy1,2, etc. are Doggy
instances.
UPDATE:
From your update it looks like you just want a list of ids for each event type. I tested this with 250k records in postgresql on my ubuntu laptop w/ a core 2 duo & 3gb of ram, and it took .35 seconds (the itertools.group_by took .72 seconds btw) to generate the dict. You mention that you have 900K records, so this should be fast enough. If it’s not it should be easy to cache/update as the records change.
from collections import defaultdict
doggies = Doggy.objects.values_list('color', 'id').order_by('color').iterator()
grouped_doggies_by_color = defaultdict(list)
for color, id in doggies:
grouped_doggies_by_color[color].append(id)
- [Django]-In Django 1.7, Python3, using Floppyforms 1.3, keep getting error "TypeError: object() takes no parameters"
- [Django]-Django REST Framework validation error: 'Enter a valid URL.'
- [Django]-When and how to validate data with Django REST Framework
- [Django]-Modifying ancestor nested Meta class in descendant
- [Django]-NameError: name PositiveSmallIntegerField is not defined
-2👍
I would change your data model so that the color and name are a one-to-many relationship with Doggy as follows:
class Doggy(models.Model):
name = models.ForeignKey('DoggyName')
color = models.ForeignKey('DoggyColor')
class DoggyName(models.Model):
name = models.CharField(max_length=40, unique=True)
class DoggyColor(models.Model):
color = models.CharField(max_length=20, unique=True)
Now DoggyName
and DoggyColor
do not contain duplicate names or colors, and you can use them to select dogs with the same name or color.
- [Django]-Django extra javascript is not working in the child page
- [Django]-Django: Long field (BigIntegerField) For MongoDB