1👍
✅
For problem 1, this makes sense because if you create a model which is refered to by other models, said model key must exist. What I’d suggest you do is look into saving multiple models with a transaction.
2 is pretty easy, just use jQuery/Javascript to show/hide the appropriate fields in the browser based on the user’s selection event.
Based on your comment, here’s an example of how I handle data to and from the server
//Submit data to server, assuming you have already extracted out the relevant data values
$("some_button").click(function(e){
$.ajax({
url : "someUURLLocation/",
type : "POST",
data : {"data" : JSON.stringify({"field1" : var1, "field2" :var2}),
dataType : "json",
success : function(results){
if (results.success == "true") {
//handle DOM insertion and other stuff
} else
alert(results.message);
}
});
}
urls.py:
from django.conf.urls import patterns, url
from $APPNAME import views
urlpatterns = patterns("",
...
...
url(r'^someURLLocation/$', views.handleDataSubmission),
...
)
views.py:
from django.http import HttpResponse
from django.utils import simplejson
def handleDataSubmission(request):
data = simplejson.loads(request.POST.get("data", None))
if data is not None:
newPost = Post.objects.create( field1 = data["field1"], field2 = data["field2"])
dataReturn = [{"val1" : newPost.title, "val2" : newPost.date}]
return HttpResponse(simplejson.dumps({"success" : "true", "data" : dataReturn}), mimetype = "application/json")
else:
return HttpResponse(simplejson.dumps({"success" : "false", "message" : "Invalid data received by server"}), mimetype = "application/json")
Source:stackexchange.com