[Fixed]-Django: Filter for get_foo_display in a Queryset

28πŸ‘

βœ…

You can’t do this. filter works at the database level, and the database doesn’t know anything about your long names. If you want to do filtering on a value, you need to store that value in the database.

An alternative is to translate the value back into the code, and filter on that:

country_reverse = dict((v, k) for k, v in COUNTRY_CHOICES)
Country.objects.filter(code=country_reverse['france'])

3πŸ‘

You can use Choices

from model_utils import Choices

class Country(models.Model):
    COUNTRY_CHOICES = Choices((
        ('FR', _(u'France')),
        ('VE', _(u'Venezuela')),
    ))

    code = models.CharField(max_length=2, choices=COUNTRY_CHOICES)

And make a query:

Country.objects.filter(code=Country.COUNTRY_CHOICES.france)
πŸ‘€Danil

1πŸ‘

You can swap values in constructor:

class PostFilter(django_filters.FilterSet):

    def __init__(self, data=None, queryset=None, prefix=None, strict=None):
        data = dict(data)
        if data.get('type'):
            data['type'] = Post.get_type_id(data['type'][0])

        super(PostFilter, self).__init__(data, queryset, prefix, strict)

    class Meta:
        model = Post
        fields = ['type']
πŸ‘€radeklos

0πŸ‘

Inspired from this answer, I did the following:

search_for = 'abc'

results = (
    [
        x for x, y in enumerate(COUNTRY_CHOICES, start=1) 
        if search_for.lower() in y[1].lower()
    ]
)

Country.objects.filter(code__in=results)
πŸ‘€raratiru

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