[Django]-Django dynamically filtering with q objects

by

125👍

✅

You’ll want to loop through the tag_list and apply a filter for each one.

tag_list = ['tag1', 'tag2', 'tag3']
base_qs = Design.objects.all()
for t in tag_list:
    base_qs = base_qs.filter(tags__tag__contains=t)

This will give you results matching all tags, as your example indicated with and. If in fact you needed or instead, you will probably need Q objects.

Edit: I think I have what you’re looking for now.

tags = ['tag1', 'tag2', 'tag3']
q_objects = Q() # Create an empty Q object to start with
for t in tags:
    q_objects |= Q(tags__tag__contains=t) # 'or' the Q objects together

designs = Design.objects.filter(q_objects)

I tested this and it seems to work really well.

Edit 2: Credit to kezabelle in #django on Freenode for the initial idea.

👤Riley Watkins

41👍

You can use this way:

my_dict = {'field_1': 1, 'field_2': 2, 'field_3': 3, ...}  # Your dict with fields
or_condition = Q()
for key, value in my_dict.items():
    or_condition.add(Q(**{key: value}), Q.OR)

query_set = MyModel.objects.filter(or_condition)

By this way you can use dynamically generated field names.
Also you can use Q.AND for AND condition.

👤Max

3👍

Just prepare a tag list first then, query like this:

tags = ['tag1', 'tag2',...]
design_list = Design.objects.filter(tags__tag__contains__in = tags)
👤Raunak Agarwal

2👍

You may need to add AND and OR conditions

    query = (Q(fild1='ENABLE'))
    # Filter by list
    query.add(Q(fild2__in=[p.code for p in Objects.field.all()]), Q.AND)

    # filter OR
    q_objects = Q(field3='9999999')
    for x in myList:
        q_objects.add(Q(field3=x.code), Q.OR)

    query.add(q_objects, Q.AND)
👤Gilson Souza

1👍

Use reduce :

from functools import reduce
design_list = Design.objects.filter(reduce(lambda q1,q2: q1 & q2,
                                           [Q(tags__tag__contains=t)
                                            for t in tag_list]))
👤Eric

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