1
Maybe this code will be helpfull:
class JobAdmin(admin.StackedInline):
model = Job
extra = 0
def get_queryset(self, request):
qs = super(JobAdmin, self).get_queryset(request)
if request.user.status in [1]:
qs = qs.filter(inspector__office=request.user.office)
return qs
def formfield_for_foreignkey(self, db_field, request=None, **kwargs):
if db_field.name == "inspector" and request.user.status == 1:
kwargs['queryset'] = Inspector.objects.filter(office=request.user.office)
return super().formfield_for_foreignkey(db_field, request, **kwargs)
P.S. Link to Django documentation: formfield_for_foreignkey
Source:stackexchange.com