[Answered ]-Django Admin: Getting request in ModelForm's constructor

1👍

✅

Ok here is how I solved it:

def formfield_for_foreignkey(self, db_field, request, **kwargs):
    if db_field.name == "category" and not request.user.has_perm('can_post_to_all'):
        kwargs["queryset"] = AnnouncementCategory.objects.filter(can_post=True)
        return db_field.formfield(**kwargs)
    return super(AnnouncementAdmin, self).formfield_for_foreignkey(db_field, request, **kwargs)

👤orwellian

[Answered ]-Are there any known issues with django and multithreading?

1👍

How can I access request.user in the ModelForm’s constructor?

To use it in the Form constructor, just pass the request to it.

class AnnouncementModelForm(forms.ModelForm):

    def __init__(self, request, *args, **kwargs):
        super(AnnouncementModelForm, self).__init__(*args, **kwargs)
        qs = request.user.foreignkeytable__set.all()
        self.fields["category"].queryset = qs

👤lprsd