[Answer]-Displaying Album title for image – Foreign Keys

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For starters, get rid of albums_(). That method makes little-to-no-sense in its current implementation. Then change ImageAdmin accordingly:

class ImageAdmin(admin.ModelAdmin):
    search_fields = ["title"]
    # Don't call albums_().  Aside from the fact that it doesn't do what you want it to do,   
    # The functionality you're looking for is already provided by Django:
    list_display = ["title", "tags_", "albums", "created"] 
    list_filter = ["tags", "albums"]

When you create a foreignkey the way you have, there will only be 1 album related to that image. From the wording in your question, it seems you either meant to put the foreignkey field in Album or you wanted a ManyToMany field

👤skzryzg

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