35👍
✅
You don’t want to use list_filter
. The property you’re looking for is list_display
. The documentation offers an example of how you can create a column that behaves like a boolean in the display. In short, you do something like this:
-
Create a method in the class:
def is_activated(self) if self.bar == 'something': return True return False
-
add the
.boolean
method attribute directly below theis_activated
method:is_activated.boolean = True
-
Add the method as a field in
list_display
:class MyAdmin(ModelAdmin):
list_display = [‘name’, ‘is_activated’] -
You’ll notice the column name is probably now “Is Activated” or something like that. If you want the column heading to change, you use the
short_description
method attribute:is_activated.short_description = "Activated"
6👍
The correct way to do this now in Django 3.0+ is with @admin.display
.
@admin.display( boolean=True, ordering='-publish_date', description='Is Published?', ) def is_published(self, obj): return obj.publish_date is not None
Source:stackexchange.com