45π
BASE_DIR
is pointing to the parent directory of PROJECT_ROOT
. You can re-write the two definitions as:
PROJECT_ROOT = os.path.dirname(os.path.abspath(__file__))
BASE_DIR = os.path.dirname(PROJECT_ROOT)
because the os.path.dirname()
function simply removes the last segment of a path.
In the above, the __file__
name points to the filename of the current module, see the Python datamodel:
__file__
is the pathname of the file from which the module was loaded, if it was loaded from a file.
However, it can be a relative path, so the os.path.abspath()
function is used to turn that into an absolute path before removing just the filename and storing the full path to the directory the module lives in in PROJECT_ROOT
.
1π
Suppose you started your project using the django-admin startproject my_new_app
command, then it creates a hierarchy as follows.
my_new_app
|
ββββmy_new_app
β β
β β settings.py
β β ...
| manage.py
Then, os.path.abspath(__file__)
returns the absolute path to the settings.py
file, os.path.dirname(os.path.abspath(__file__))
returns the path to the inner my_new_app
folder and os.path.dirname(os.path.dirname(os.path.abspath(__file__)))
returns the path to the outer my_new_app
folder.
In more recent versions of Django (e.g. version 4.2.5), instead of os
, pathlib
module is used, so an equivalent construct is:
from pathlib import Path
BASE_DIR = Path(__file__).resolve().parent.parent
PROJECT_ROOT = Path(__file__).resolve().parent
Thereβs a special case where if settings.py
is already in the root directory on your environment (e.g. the C drive on a local machine) so that its path looks like C:\settings.py
, then BASE_DIR == PROJECT_ROOT
may be True. This is probably not how it should be, so if BASE_DIR and PROJECT_ROOT are the same, then you probably need to re-structure your project.
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