[Fixed]-Custom id field in Django model

by

27👍

✅

https://docs.djangoproject.com/en/dev/topics/db/models/#automatic-primary-key-fields

If you’d like to specify a custom primary key, just specify
primary_key=True on one of your fields. If Django sees you’ve
explicitly set Field.primary_key, it won’t add the automatic id
column.

So you want (from https://docs.djangoproject.com/en/dev/ref/models/fields/#uuidfield)

import uuid
from django.db import models

class MyUUIDModel(models.Model):
    id = models.UUIDField(primary_key=True, default=uuid.uuid4, editable=False)
    # other fields

you don’t have to name the field id I think.

👤eugene

0👍

On my project, this is what I did. Supposed that you have a sample model with a custom id and the autofield ID:

class Product(models.Model)
      product_tag_number = models.CharField(max_length=50, editable=False, unique=True) # this is my custom ID
      
      def save(self, *args, **kwargs): # I override my save function in here. 
            super().save(*args, **kwargs)
            self.set_ptn() # And then call my own function in here to generate such custom ID combining the autoField ID and the UUID.

      def set_ptn(self): # And this is the function for generating the custom ID for the item
            ......
            And then your function goes here for combining them
            ......

Note: Doing this method will not affect and will not use the AutoField generated by Django for you. But it’s your call if you will use this as your primary key.

👤dev_ren

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